WebMar 18, 2024 · 1 Answer. If any string contain a,b & it is divisible by 3 than it has 3 states i.e. q0,q1,q2. One is having remainder 0 Second is having remainder 1 Third is having remainder 2. WebJun 18, 2024 · Problem – Construct a DFA machine over input alphabet = {0, 1}, that accepts: Odd number of 0’s or even number of 1’s Odd …
4.10. DFA for even length of a and b - YouTube
Webthis Dfa will accept exactly two a's and one or more b. State q3 is having transistion on 'a' to q5(arrow is missing) Share. Cite. Follow edited Jun 14, 2015 at 15:54. answered Jun 14, 2015 at 15:48. Ravi Roy ... Why is the number of states for DFA is … WebNov 20, 2024 · For example, having seen the input ABAABCA, we would be in state (even A's, even B's, 1 C) and then if we see an A we would pass to state (odd A's, even B's, 1 C). I'll leave it to you to determine which of the twelve states should be the start and which should be the final state. photo print shop software for windows 10
CSE 105, Fall 2024 - Homework 2 Solutions - University of …
WebDec 2, 2015 · Your answer is incorrect. It rejects strings that are even and therefore should be accepted, like $1100$, and accepts strings that are odd and therefore should be rejected, like $1$. The correct automaton needs to remember whether the last character read was $1$ or $0$, so we need two states: the initial state and an accepting state. WebAnswered: For the language L on {a, b}, if all… bartleby. ASK AN EXPERT. Engineering Computer Science For the language L on {a, b}, if all strings in L contain an even … WebJan 22, 2024 · Step-1 Exactly same as for binary, use figure-1. Total number of edges in transition diagram figure-12 are 15 = Q × Σ = 5 * 3 (a complete DFA). And this DFA can accept all strings consist over {0, 1, 2} those decimal equivalent is divisible by 5. how does remote keyless entry work